CodeChef SEPT17 Problem: MINPERM

Problem:Minimum Good Permutation

A permutation of length n is an array of size n consisting of n distinct integers in the range [1, n]. For example, (3, 2, 4, 1) is a permutation of length 4, but (3, 3, 1, 4) and (2, 3, 4, 5) are not, as (3, 3, 1, 4) contains duplicate elements, and (2, 3, 4, 5) contains elements not in range [1,4].
A permutation p of length n is good if and only if for any 1 ≤ i ≤ n, p_i ≠ i.
Please find the lexicographically smallest good permutation p.
Definition for "lexicographically smaller":
For two permutations p and q, we say that p is lexicographically smaller than q if and only if there exists a index 1 ≤ l ≤ n such that:

• For any 1 ≤ i < l, p_i = q_i. Note that if l = 1, this constraint means nothing.
• and, p_l < q_l.

For example, (2, 3, 1, 4) < (2, 3, 4, 1) < (3, 4, 1, 2). The lexicographically smallest permutation is, of course, (1, 2, ..., n), though this one is not good.

Input 
First line of the input contains an integer T denoting number of test cases.
For each test case, the only line contains an integer n.

Output 
For each test case, output the lexicographically smallest good permutation of length n. It's guaranteed that this permutation exists

Constraints :

• 1 ≤ T ≤ 10
• 2 ≤ n ≤ 10⁵

Subtask :

• Subtask #1 (17 points): 2 ≤ n ≤ 9
• Subtask #2 (83 points): Original Constraints

Example

Input:
4
2
3
5
6

Output:
2 1
2 3 1
2 1 4 5 3
2 1 4 3 6 5

 

Explanation

Example case 1. The only good permutation of length 2 is (2, 1).
Example case 2. Consider all permutations of length 3, they are(in lexicographically order):

• p = (1, 2, 3), it's not good since p[1] = 1, p[2] = 2 and p[3] = 3;
• p = (1, 3, 2), it's not good since p[1] = 1;
• p = (2, 1, 3), it's not good since p[3] = 3;
• p = (2, 3, 1), it's good since p[1] ≠ 1, p[2] ≠ 2 and p[3] ≠ 3;
• p = (3, 1, 2), it's good since p[1] ≠ 1, p[2] ≠ 2 and p[3] ≠ 3;
• p = (3, 2, 1), it's not good since p[2] = 2.

Thus the minimum good one is (2, 3, 1).
Example case 3. Consider two good permutations for third test case: p=(2, 1, 4, 5, 3) and q=(2, 4, 1, 5, 3), then p < q. You can check lexicographically condition as follows. Find the first index where the entries of two permutations are different, and compare those entries. For example, in this case, the first position where the entries differ is index 2. You can see that p[2] < q[2], as 1 < 4, so p is lexicographically smaller than q.


Solutions :

 

#include<iostream>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n,temp;
        cin>>n;
        int arr[n];
        for(int i=0; i<n; i++)
            arr[i]=i+1;
        for(int i=1; i<n; i+=2)
        {
            if(arr[i] == i+1)
            {
                temp = arr[i];
                arr[i]=arr[i-1];
                arr[i-1]=temp;
            }
        }
         for(int i=1; i<n; i++)
        {
            if(arr[i] == i+1)
            {
                temp = arr[i];
                arr[i]=arr[i-1];
                arr[i-1]=temp;
            }
        } 
        for(int i=0 ;i<n;i++)
            cout<<arr[i]<<" ";
        cout<<endl;
    }
    return 0;
}